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Type : MCQ

Question Statement :

The perimeter of an isosceles triangle is 28 cm and the ratio of the length of the lateral side to that of the base is 5:4. The area of the triangle is:

$\sqrt{21} c m^{2}$
$3 \sqrt{21} c m^{2}$
$4 \sqrt{21} c m^{2}$
$8 \sqrt{21} c m^{2}$